A) execute SHM about the origin
B) move to the origin and remain at rest
C) move to infinity
D) execute oscillatory but not SHM
Correct Answer: D
Solution :
Component of force on charge + Q at P, along x-axis, \[{{F}_{x}}=\frac{2Qq}{4\pi {{\varepsilon }_{0}}({{a}^{2}}+{{x}^{2}})}\cos \theta \] \[=\frac{2Qq}{4\pi {{\varepsilon }_{0}}({{a}^{2}}+{{x}^{2}})}\times \frac{x}{\sqrt{{{a}^{2}}+{{x}^{2}}}}\] \[=\frac{2Qqx}{4\pi {{\varepsilon }_{0}}{{({{a}^{2}}+{{x}^{2}})}^{3/2}}}\] Which is not directly proportional to x. So, motion is oscillatory but not SHM.You need to login to perform this action.
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