A) \[F{{e}^{3+}}\]
B) \[F{{e}^{2+}}\]
C) \[C{{o}^{2+}}\]
D) \[C{{o}^{3+}}\]
Correct Answer: A
Solution :
\[F{{e}^{3+}}\xrightarrow{{}}[Ar]\,\,3{{d}^{5}}4{{s}^{0}}\] Number of unpaired electrons = 5.
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