A) 100 Hz
B) 99 Hz
C) 96 Hz
D) 103 Hz
Correct Answer: B
Solution :
Each tuning forck gives 3 beats with the next, so the difference in the frequencies of two consecutive forks is 3. \[\therefore \] \[{{f}_{26}}={{f}_{1}}+(n-1)\times -\,3\] \[f=2f+(26-1)\times -3\] \[f=75\,Hz.\] \[\therefore \] Frequency of 18th tuning fork \[{{f}_{18}}={{f}_{1}}+(18-1)\times -\,3\] \[=2\times 75+17\times -\,3\] \[=150-51-99\,Hz\].You need to login to perform this action.
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