A) \[2T\]
B) \[4T\]
C) \[{{(2)}^{1/2}}T\]
D) \[2{{(2)}^{1/2}}T\]
Correct Answer: C
Solution :
Gas obeys the equation \[P{{V}^{3/2}}=\] constant Comparing with\[P{{V}^{\gamma }}=\]constant \[\gamma =\frac{3}{2}\] For adiabatic process \[{{T}_{1}}V_{1}^{\gamma -1}={{T}_{2}}V_{2}^{\gamma -1}\] \[T{{(V)}^{3/2-1}}={{T}_{2}}{{\left( \frac{V}{2} \right)}^{3/2-1}}\] \[{{T}_{2}}=T{{(2)}^{3/2-1}}\] \[={{(2)}^{1/2}}T\]You need to login to perform this action.
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