A) 8 times
B) 1/4 times
C) 2 times
D) 4 times
Correct Answer: D
Solution :
Resonance frequency\[f=\frac{1}{2\pi \sqrt{LC}}\] For the circuit to remain in resonance, \[\sqrt{LC}=\]constant or \[{{L}_{1}}{{C}_{1}}={{L}_{2}}{{C}_{2}}\] or \[LC={{L}_{2}}\frac{C}{4}\] \[\therefore \] \[{{L}_{2}}=4L\] \[\therefore \] Inductance should be change to four times.You need to login to perform this action.
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