A) 8r
B) 2r
C) 4r
D) \[2\sqrt{2}r\]
Correct Answer: C
Solution :
Radius of Bohr orbit \[r\propto {{n}^{2}}\] \[\frac{{{r}_{1}}}{{{r}_{2}}}={{\left( \frac{{{n}_{1}}}{{{n}_{2}}} \right)}^{2}}\] \[\Rightarrow \] \[\frac{r}{{{r}_{2}}}={{\left( \frac{1}{2} \right)}^{2}}\] \[\Rightarrow \] \[\frac{r}{{{r}_{2}}}=\frac{1}{4}\] \[\Rightarrow \] \[{{r}_{2}}=4r.\]You need to login to perform this action.
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