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JIPMER Jipmer Medical Solved Paper-2006

  • question_answer
    The entropy values (in \[J{{K}^{-1}}mo{{l}^{-1}}\]) of \[{{H}_{2}}(g)=130.6,\]\[C{{l}_{2}}(g)=223.0\]and\[HCl(g)=186.7\] at 298 K and 1 atm pressure. Then entropy change for the reaction: \[{{H}_{2}}(g)+C{{l}_{2}}(g)\xrightarrow{{}}2HCl(g)\]is:

    A)  + 540.3

    B)                                         +727.3                 

    C)         -166.9                                  

    D)         +19.8

    Correct Answer: D

    Solution :

    \[\Delta S{}^\circ =2S{{{}^\circ }_{HCl}}-(S{{{}^\circ }_{{{H}_{2}}}}+S{{{}^\circ }_{C{{l}_{2}}}})\] \[=2\times 186.7-(130.6+223.0)\] \[=19.8\,J{{K}^{-1}}mo{{l}^{-1}}\]


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