A) Conversion of pyruvic acid to acetyl Co-A
B) Electron transport chain
C) Glycolysis
D) Krebs cycle
Correct Answer: B
Solution :
In glycolysis 4 ATP and \[2\,NAD{{H}_{2}}\] molecules are formed. These \[2\,NAD{{H}_{2}}\] molecules go to electron transport chain. In oxidative decarboxylation no ATP molecule is formed but two molecules of \[NAD{{H}_{2}}\] are formed from two molecules of pyruvate. These two \[NAD{{H}_{2}}\] go to electron transport chain. In Krebs cycle 2 ATP, 6 NADH, and \[2\,FAD{{H}_{2}}\] molecules are formed from two molecule of acetyl Co- A. These \[NAD{{H}_{2}}\] and \[2\,FAD{{H}_{2}}\], go to electron transport chain. In electron transport chain all \[NAD{{H}_{2}}\] and \[FAD{{H}_{2}}\] pass to electron carriers and yield 3 ATP and 2 ATP molecules per \[NAD{{H}_{2}}\] and \[FAD{{H}_{2}}\] respectively. Thus, 4 ATP are formed in glycolysis 2 ATP in Krebs cycle and \[\frac{\text{34 ATP from electron transport chain}}{\text{4}0\text{ ATP}}\] 2 ATP molecules are used during glycolysis. So, net gain of ATP molecules during one complete oxidation of a glucose molecule is 38 ATP.
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