A) \[20{}^\circ C\]
B) \[320{}^\circ C\]
C) \[-20{}^\circ C\]
D) \[40{}^\circ C\]
Correct Answer: C
Solution :
Key Idea: The temperature of inversion is higher than the neutral temperature by the same amount as the neutral temperature is higher than the temperature of cold junction. As per Key Idea \[{{t}_{n}}-{{t}_{0}}={{t}_{i}}-{{t}_{n}}\] \[\Rightarrow \] \[{{t}_{0}}=2{{t}_{n}}-{{t}_{i}}\] Given, \[{{t}_{i}}=620{}^\circ C,\,{{t}_{n}}=300{}^\circ C\] Hence, \[{{t}_{0}}=\] temperature of cold junction \[=2\times 300-620\] \[=600-620=-\,20{}^\circ C\] NOTE: Neutral temperature does not change for a metal whether the temperature of cold junction and inversion temperature change by any value.
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