A) c + a - b
B) c - a - b
C) a + b + c
D) a + b - c
Correct Answer: B
Solution :
Key Idea: The energy released per nuclear reaction is the resultant binding energy. Binding energy of \[({}_{1}^{2}H+{}_{1}^{3}H)=a+b\] Binding energy of \[{}_{2}^{4}\text{He}\,\text{=}\,\text{c}\] In a nuclear reaction the resultant nucleus is more stable than the reactants. Hence, binding energy of \[{}_{2}^{4}\text{He}\] will be more than that of\[({}_{1}^{2}\text{H}\,\text{+}\,{}_{1}^{3}\text{H)}\text{.}\] Thus, energy released per nucleon = resultant binding energy \[=c-(a+b)=c-a-b\]You need to login to perform this action.
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