JIPMER Jipmer Medical Solved Paper-2007

  • question_answer
    The total energy of an electron in the first excited state of hydrogen is about - 3.4 eV. Its kinetic energy in this state is

    A) -3.4eV 

    B)                        -6.8eV                  

    C)         6.8eV                  

    D)        3.4eV

    Correct Answer: D

    Solution :

    Key Idea: The kinetic energy is equal to the negative of total energy. Kinetic energy of electron \[K=\frac{Z{{e}^{2}}}{8\pi {{\varepsilon }_{0}}r}\] Potential energy of electron \[U=-\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{Z{{e}^{2}}}{r}\] \[\therefore \] Total energy \[E=K+U=\frac{Z{{e}^{2}}}{8\pi {{\varepsilon }_{0}}r}-\frac{Z{{e}^{2}}}{4\pi {{\varepsilon }_{0}}r}\] or            \[E=-\frac{Z{{e}^{2}}}{8\pi {{\varepsilon }_{0}}r}\] or            \[E=-K\] or            \[K=-E=-\,(-3.4)=3.4\,eV\]


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