A) one-fifth
B) five
C) one
D) two
Correct Answer: D
Solution :
In alkaline solution, \[KMn{{O}_{4}}\] is reduced to \[Mn{{O}_{2}}\] (colourless). \[2KMn{{O}_{4}}+2{{H}_{2}}O\xrightarrow{\,}\,2Mn{{O}_{4}}+2KOH\,\,+3\,[O]\,KJ+3[O]\,\xrightarrow{\,}\,KI{{O}_{3}}\] ____________________________________________________________________ \[2KMn{{O}_{4}}+2{{H}_{2}}O+KI\xrightarrow{\,}\,2Mn{{O}_{2}}+2KOH+KI{{O}_{3}}\] ____________________________________________________________________ Hence, two moles of \[KMn{{O}_{4}}\] are reduced by one mole of KI.
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