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JIPMER Jipmer Medical Solved Paper-2007

  • question_answer
    Equilibrium constants \[{{K}_{1}}\] and \[{{K}_{2}}\] for the following equilibria \[NO(g)+\frac{1}{2}{{O}_{2}}N{{O}_{2}}(g)\] and \[2N{{O}_{2}}(g)2NO(g)+{{O}_{2}}(g)\] are related as

    A)  \[{{K}_{2}}=\frac{1}{{{K}_{1}}}\]

    B)                         \[{{K}_{2}}=K_{1}^{2}\]               

    C)         \[{{K}_{2}}=\frac{{{K}_{1}}}{2}\]              

    D)         \[{{K}_{2}}=\frac{1}{K_{1}^{2}}\]

    Correct Answer: D

    Solution :

    (i) \[NO(g)+\frac{1}{2}{{O}_{2}}(g)N{{O}_{2}}(g)\] So           \[{{K}_{1}}=\frac{[N{{O}_{2}}]}{[NO]\,\,{{[{{O}_{2}}]}^{1/2}}}\] ?(i) (ii) \[2N{{O}_{2}}(g)2NO+{{O}_{2}}(g)\] So           \[{{K}_{2}}=\frac{{{[NO]}^{2}}[{{O}_{2}}]}{{{[N{{O}_{2}}]}^{2}}}\]             ?(ii) From Eq. (i) \[K_{1}^{2}=\frac{{{[N{{O}_{2}}]}^{2}}}{{{[NO]}^{2}}[{{O}_{2}}]}\] or            \[\frac{1}{K_{1}^{2}}=\frac{{{[NO]}^{2}}[{{O}_{2}}]}{{{[N{{O}_{2}}]}^{2}}}\]         ?(iii) From Eqs. (ii) and (iii) \[{{K}_{2}}=\frac{1}{K_{1}^{2}}\]


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