A) \[{{H}_{2}}\]
B) \[{{N}_{2}}\]
C) \[{{O}_{2}}\]
D) \[S{{O}_{2}}\]
Correct Answer: D
Solution :
When copper reacts with hot and cone. \[{{H}_{2}}S{{O}_{4}}\] \[S{{O}_{2}}\] is produced. \[Cu+2{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}CuS{{O}_{4}}+S{{O}_{2}}+4{{H}_{2}}O\]
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