JIPMER Jipmer Medical Solved Paper-2008

  • question_answer
    The change in entropy for the fusion of 1 mole of ice is [mp of ice = 273 K, molar enthalpy of fusion for ice \[=6.0\,kJ\,mo{{l}^{-1}}\]]

    A)  \[11.73\,J{{K}^{-1}}mo{{l}^{-1}}\]           

    B)  \[18.84\,J{{K}^{-1}}mo{{l}^{-1}}\]

    C)         \[21.97\,J{{K}^{-1}}mo{{l}^{-1}}\]

    D)         \[24.47\,J{{K}^{-1}}mo{{l}^{-1}}\]

    Correct Answer: C

    Solution :

    Entropy change of fusion \[\Delta {{S}_{f}}=\frac{\Delta {{H}_{f}}}{T}\] \[\Delta {{H}_{f}}=60\times {{10}^{3}}J,\,mo{{l}^{-1}},T=273\,K\] \[\Delta {{S}_{f}}=\frac{60\times {{10}^{3}}}{273}\] \[=21.97\,J\,{{K}^{-1}}\,mo{{l}^{-1}}\]


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