A) 60 K
B) 75 K
C) 150 K
D) 225 K
Correct Answer: A
Solution :
Here \[{{V}_{1}}=10L,\] \[{{V}_{2}}=2L\] \[{{p}_{1}}=1\,atm,\] \[{{p}_{2}}=1\,atm\] \[{{T}_{1}}=300\,K,\,{{T}_{2}}=?\] \[\frac{{{p}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{p}_{2}}{{V}_{2}}}{{{T}_{2}}}\] \[\frac{1\times 10}{300}=\frac{1\times 2}{{{T}_{2}}}\] \[{{T}_{2}}=\frac{300\times 2}{10}=60\,K\]You need to login to perform this action.
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