A) 200 J
B) 100 J
C) zero
D) 1000 J
Correct Answer: B
Solution :
Net work done in sliding a body up to a height h on inclined plane = Work done against gravitational force + Work done against frictional force \[\Rightarrow \] \[W={{W}_{g}}+{{W}_{f}}\] ?(i) \[{{W}_{g}}=mgh=2\times 10\times 10=200\,J\] Putting in Eq. (i), we get \[300=200+{{W}_{f}}\] \[\Rightarrow \] \[{{W}_{f}}=300-200=100\,J\]
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