JIPMER Jipmer Medical Solved Paper-2009

  • question_answer
    The frequency of a light wave in a material is \[2\times {{10}^{14}}Hz\] and wavelength is\[5000\,\overset{\text{o}}{\mathop{\text{A}}}\,\]. The refractive index of material will be

    A)  1.40                      

    B)         1.50                      

    C)  3.00                      

    D)         1.33

    Correct Answer: C

    Solution :

    Velocity of light waves in material is \[v=v\lambda \]                                               ?(i) Refractive index of material is \[\mu =\frac{c}{v}\]                                        ?(ii) where c is speed of light in vacuum or air. or            \[\mu =\frac{c}{v\lambda }\]                                      ?(iii) Given, \[v=2\times {{10}^{14}}Hz,\] \[\lambda =5000\,\overset{\text{o}}{\mathop{\text{A}}}\,=5000\times {{10}^{-10}}m,\] \[c=3\times {{10}^{8}}m\text{/}s\] Hence, from Eq. (iii), we get \[\mu =\frac{3\times {{10}^{8}}}{2\times {{10}^{14}}\times 5000\times {{10}^{-10}}}=3.00\]


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