A) 20\[\Omega \]
B) 2\[\Omega \]
C) 0.2\[\Omega \]
D) 2k\[\Omega \]
Correct Answer: B
Solution :
Let \[{{i}_{a}}\] is the current flowing through ammeter and \[i\] is the total current. So, a current \[i-{{i}_{a}}\] will flow through shunt resistance. Potential difference across ammeter and shunt resistance is same. i.e., \[{{i}_{a}}\times R=(i={{i}_{a}})\times S\] or \[S=\frac{{{i}_{a}}R}{i-{{i}_{a}}}\] ?(i) Given, \[{{i}_{a}}=100A,\,i=750A,\,R=13\,\Omega \] Hence, \[S=\frac{100\times 13}{750-100}=2\,\Omega \]You need to login to perform this action.
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