A) \[2\Omega \]
B) \[3\Omega \]
C) \[6\Omega \]
D) \[1\Omega \]
Correct Answer: B
Solution :
The situation can be depicted as shown in figure. As resistances S and \[6\,\Omega \] are in parallel their effective resistance is \[\frac{6S}{6+S}\Omega \] As the bridge is balanced, hence it is balanced Wheatstones bridge. For balancing condition, \[\frac{P}{Q}=\frac{R}{\left( \frac{6S}{6+S} \right)}\] or \[\frac{2}{2}=\frac{2(6+S)}{6S}\] or \[3S=6+S\] or \[S=3\,\Omega \]You need to login to perform this action.
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