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JIPMER Jipmer Medical Solved Paper-2009

  • question_answer
    H-O-H bond angle in \[{{H}_{2}}O\] is \[104.5{}^\circ \]and not \[109{}^\circ \,28\] because of

    A)  lone pair-lone pair repulsion

    B)  lone pair-bond pair repulsion

    C)  bond pair-bond pair repulsion

    D)  high electronegativity of oxygen

    Correct Answer: A

    Solution :

    The hybridisation of oxygen in water molecule is\[s{{p}^{3}}\]. So, water molecule must be tetrahedral and have bond angle \[109{}^\circ 28\]. But due to the presence of two lone pair of electrons on oxygen atom (repulsion between lone pair-lone pair) the bond angle decreases about \[104.5{}^\circ \] and the geometry becomes distorted tertrahedral or V-shaped.


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