JIPMER Jipmer Medical Solved Paper-2009

  • question_answer
    Under the influence of a uniform magnetic field a charged particle is moving in a circle of radius R with constant speed v. The time period of the motion

    A)  depends on v and not on R

    B)  depends on both R and v

    C)  is independent of both R and v

    D)  depends on R and not on v

    Correct Answer: C

    Solution :

    When magnetic field is perpendicular to motion of charged particle, then Centripetal force = magnetic force \[i.e.,\] \[\frac{m{{v}^{2}}}{R}=Bqv\] or            \[R=\frac{mv}{Bq}\] Further, time period of the motion \[T=\frac{2\pi R}{v}=\frac{2\pi \left( \frac{mv}{Bq} \right)}{v}\] or            \[T=\frac{2\pi m}{Bq}\] It is independent of both R and v.


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