A) \[1\,m{{s}^{-1}}\]
B) \[2\,m{{s}^{-1}}\]
C) \[1.5\,m{{s}^{-1}}\]
D) \[1.25\,m{{s}^{-1}}\]
Correct Answer: D
Solution :
Equation of wave \[y=5\,\sin \left( \frac{t}{0.04}-\frac{x}{4} \right)\] The standard equation of a wave in the given form is \[y=a\sin \left( \omega t-\frac{2\pi x}{\lambda } \right)\] Comparing the given equation with the standard equation, we get \[a=5\] and \[\omega =\frac{1}{0.04}=25\] Therefore, maximum velocity of particles of the medium, \[{{v}_{\max }}=a\omega =5\times 25=125\,cm{{s}^{-1}}=1.25\,m{{s}^{-1}}\]
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