A) \[2\,\Omega \]
B) \[3\,\Omega \]
C) \[4\,\Omega \]
D) \[5\,\Omega \]
Correct Answer: C
Solution :
The equivalent circuit can be redrawn as We have, \[\frac{P}{Q}=\frac{R}{S}\] i.e., \[\frac{4}{4}=\frac{4}{4}\] So, the given circuit is a balanced Wheatstones bridge. Hence, the equivalent resistance \[{{R}_{AB}}=\frac{(4+4)\times (4+4)}{(4+4)+(4+4)}=\frac{8\times 8}{8+8}=\frac{64}{16}=4\,\Omega \]You need to login to perform this action.
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