A) \[\frac{r}{4}\]
B) \[\frac{r}{2}\]
C) 2r
D) 4r
Correct Answer: D
Solution :
In a perpendicular magnetic field, Magnetic force = centripetal force \[i.e,\] \[Bqv=\frac{m{{v}^{2}}}{r}\Rightarrow r=\frac{mv}{Bq}\] \[\therefore \] \[\frac{{{r}_{1}}}{{{r}_{2}}}=\frac{{{v}_{1}}}{{{v}_{2}}}\times \frac{{{B}_{2}}}{{{B}_{1}}}\] \[\frac{{{r}_{1}}}{{{r}_{2}}}=\frac{1}{2}\times \frac{1}{2}\] \[{{r}_{2}}=4{{r}_{1}}\] \[\Rightarrow \] \[{{r}_{2}}=4r\]You need to login to perform this action.
You will be redirected in
3 sec