A) 10 V
B) 20V
C) 35V
D) 70V
Correct Answer: C
Solution :
Given, \[\phi =5{{t}^{3}}-100\,t+300\] \[e=-\frac{d\phi }{dt}=\frac{-d}{dt}(5{{t}^{3}}-100t+300)\] \[=-(15{{t}^{2}}-100+0)\] \[=-15{{t}^{2}}+100\] \[\therefore \] \[\frac{e}{t}=-15{{(3)}^{2}}+100=-15\times 9+100\] \[=-135+100=-35\,V\] Minus sign signifies the Lenzs law.You need to login to perform this action.
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