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JIPMER Jipmer Medical Solved Paper-2010

  • question_answer
    In 0.1 s, the current in a coil increases from 1 A to 1.5A. If inductance of coil is 60 mH, then induced current in external resistance of \[3\,\Omega \] will be

    A)  1 A        

    B)                                         0.5 A                    

    C)  0.2 A                    

    D)         0.1 A

    Correct Answer: D

    Solution :

    Induced emf, \[\left| \,e\, \right|=L\frac{di}{dt}=(60\times {{10}^{-3}})\times \frac{(1.5-1)}{0.1}\] \[=\frac{60\times {{10}^{-3}}\times 0.5}{0.1}=0.3\,V\] Induced current, \[i=\frac{e}{R}=\frac{0.3}{3}=0.1\,A\]


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