A) \[{{[Mn{{O}_{4}}]}^{-}}\]
B) \[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}\]
C) \[{{[Fe{{(CN)}_{6}}]}^{3-}}\]
D) \[{{[Cr{{({{H}_{2}}O)}_{6}}]}^{3+}}\]
Correct Answer: A
Solution :
In \[{{[Mn{{O}_{4}}]}^{-}},\]the oxidation state of Mn is +7. \[Mn\,(25)=[Ar]\,3{{d}^{5}}4{{s}^{2}}\] \[M{{n}^{7+}}=[Ar]\] Thus, in \[{{[Mn{{O}_{4}}]}^{-}}\] no d-electron is present.
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