A) 1st IE of C > 1st IE of B
B) 1st IE of C < 1st IE of B
C) 2nd IE of C > 2nd IE of B
D) Both (b) and (c)
Correct Answer: A
Solution :
The minimum amount of energy required to remove the most loosely bound electron from an isolated gaseous atom so as to convert it into a gaseous cation, is called its ionisation energy. Because the size of C is smaller than that of the B due to effective nuclear charge, hence 1st IE of C > 1st IE of B
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