question_answer

Considering \[{{H}_{2}}O\] as weak field ligand, the number of unpaired electrons in\[{{[Mn{{({{H}_{2}}O)}_{6}}]}^{2+}}\]will be (Atomic number of Mn = 25)

A)  five                                      

B)  two                      

C)  four                                     

D)  three

Correct Answer: A

Solution :

Mn in \[{{[Mn{{({{H}_{2}}O)}_{6}}]}^{2+}}\]is present as\[M{{n}^{2+}}(3{{d}^{5}})\]. \[s{{p}^{3}}{{d}^{2}}\]hybridization occurs in \[{{[Mn({{H}_{2}}O)]}^{2+}}.\] Due to the presence of weak field ligand pairing of electron does not take place, hence the number of unpaired electrons is five.