A) \[C{{H}_{3}}C{{H}_{2}}Cl+HCl\]
B) \[C{{H}_{3}}C{{H}_{2}}Cl+{{H}_{2}}O+S{{O}_{2}}\]
C) \[C{{H}_{3}}C{{H}_{2}}Cl+HCl+S{{O}_{2}}\]
D) \[C{{H}_{3}}C{{H}_{2}}Cl+S{{O}_{2}}+C{{l}_{2}}\]
Correct Answer: C
Solution :
\[\underset{ethyl\,alcohol}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,+\underset{\begin{smallmatrix} thionyl \\ chloride \end{smallmatrix}}{\mathop{SOC{{l}_{2}}}}\,\to C{{H}_{3}}C{{H}_{2}}Cl+HCl+S{{O}_{2}}\uparrow \] This method is preferred for the preparation of alkyl halide because both by product of the reaction (i.e., \[S{{O}_{2}}\] and \[HCl\]) are gases and can easily escape leaving behind pure alkyl halide.
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