A) 200 N
B) 400 N
C) 600 N
D) 800N
Correct Answer: D
Solution :
Yaungs modulus \[Y=\frac{FL}{Al}\] or \[F=\frac{YAl}{L}\] or\[F\propto A\]or\[F\propto {{r}^{2}}\]or\[F\propto {{d}^{2}}\] \[\therefore \] \[\frac{{{F}_{1}}}{{{F}_{2}}}=\frac{d_{1}^{2}}{d_{2}^{2}}\] Given, \[{{d}_{1}}=d,\]\[{{d}_{2}}=2d,\]\[{{F}_{1}}=200\,N\] \[\therefore \] \[\frac{200}{{{F}_{2}}}=\frac{{{(d)}^{2}}}{{{(2d)}^{2}}}=\frac{1}{4}\] or \[{{F}_{2}}=4\times 200=800N\]
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