A) 2.4 kHz
B) 0.24 kHz
C) 1.6 kHz
D) 1.2 kHz
Correct Answer: C
Solution :
The reflected sound appears to propagate in a direction opposite to that of moving engine. Thus, the source and the observer can be presumed to approach each other with same velocity. \[v=\frac{v\,(v+{{v}_{0}})}{(v-{{v}_{s}})}=v\left( \frac{v+{{v}_{s}}}{v-{{v}_{s}}} \right)\] \[(\because \,\,{{v}_{0}}={{v}_{s}})\] \[v=1.2\,\left( \frac{350+50}{350-50} \right)=1.6\,kHz.\]You need to login to perform this action.
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