A) chain isomerism
B) position isomerism
C) chain as well as position isomerism
D) functional isomerism
Correct Answer: C
Solution :
\[C{{H}_{3}}-\underset{Br}{\overset{C{{H}_{3}}}{\mathop{\underset{\mathbf{|}}{\overset{\mathbf{|}}{\mathop{C}}}\,}}}\,-C{{H}_{3}}\] \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}Br\] Here, the chain of carbon atoms and the position of functional group both are different, they exhibit chain as well as position isomerism.You need to login to perform this action.
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