A) \[0{}^\circ \]
B) \[45{}^\circ \]
C) \[90{}^\circ \]
D) \[180{}^\circ \]
Correct Answer: C
Solution :
\[{{y}_{1}}=a\sin \,(\omega t-x)\] \[=a\cos \left( \frac{\pi }{2}+x-\omega t \right)\] and \[{{y}_{2}}=b\,\,\cos \,(\omega t-x)\] Phase difference\[\Delta \theta =\frac{\pi }{2}\]You need to login to perform this action.
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