A) 22.17\[g{{L}^{-1}}\]
B) 58.14\[g{{L}^{-1}}\]
C) 61.26\[g{{L}^{-1}}\]
D) 75.43\[g{{L}^{-1}}\]
Correct Answer: B
Solution :
From the equation \[\pi =CRT\]or \[C=\frac{\pi }{RT}\] \[=8.21\text{ }atm\text{/}0.0821\text{ }L\text{ }atm\text{ }{{K}^{-1}}\text{ }mo{{l}^{-1}}\times 310\,K\] \[=0.323\text{ }M=0.323\times 180\text{ }g{{L}^{-1}}\] \[=58.14\,g\,{{L}^{-1}}\]You need to login to perform this action.
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