A) \[6.17\times {{10}^{-21}}J{{K}^{-1}}\]
B) \[6.17\times {{10}^{-21}}\,kJ{{K}^{-1}}\]
C) \[6.17\times {{10}^{20}}\,J{{K}^{-1}}\]
D) \[7.16\times {{10}^{-20}}\,J{{K}^{-1}}\]
Correct Answer: A
Solution :
Average kinetic energy per molecule \[=\frac{3}{2}KT\] \[=\frac{3}{2}\times 1.38\times {{10}^{-23}}\times 298\] \[=6.17\times {{10}^{-21}}J{{K}^{-1}}\,molecul{{e}^{-1}}\]
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