A) \[10{}^\circ C\]
B) \[0{}^\circ C<<{{T}_{m}}<20{}^\circ C\]
C) \[20{}^\circ C\]
D) above \[20{}^\circ C\]
Correct Answer: A
Solution :
From, Heat transfer principle, Heat given = Heat taken {Neglecting heat losses} \[{{m}_{1}}{{s}_{1}}(100-t)={{m}_{2}}L+{{m}_{2}}{{s}_{2}}(t-0)\] \[50\times 1\,(100-t)=50\times 80+50\times 1\,(t-0)\] \[5000-50\,t=4000+50\,t\] \[t=\frac{1000}{100}=10\] Final temp\[t=10{}^\circ C\].
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