A) \[\frac{2}{\lambda }\]
B) \[2\lambda \]
C) \[4\lambda \]
D) \[\frac{4}{\lambda }\]
Correct Answer: C
Solution :
According to Bohrs atomic concept, an electron always move in the orbit with angular momentum is integral multiple of\[\frac{h}{2\pi }\] \[mvr=\frac{nh}{2\pi }\] \[r=\frac{nh}{2\pi mv}=\frac{n\lambda }{2\pi }\] \[\left\{ \because \,\,\lambda =\frac{h}{mv} \right\}\] for, \[n=4\] \[r=\frac{4\lambda }{2\pi }\Rightarrow \frac{2\lambda }{\pi }\] Circumference\[=2\pi r=2\pi \frac{2\lambda }{\pi }=4\lambda .\]You need to login to perform this action.
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