A particle moves towards east for 2 s with velocity 15 m/s and move towards north for 8s with velocity 5 m/s. Then, average velocity of the particle is
A) 1 m/s
B) 5 m/s
C) 7 m/s
D) 10 m/s
Correct Answer:
B
Solution :
Distance \[AB=2\times 15=30\,m\] Distance \[BC=8\times 5=40\,m\] Displacement \[(AC)=\sqrt{{{(AB)}^{2}}+{{(BC)}^{2}}}\] \[=\sqrt{{{(30)}^{2}}+{{(40)}^{2}}}\] \[=50\,m\] Total time of travel = 2 + 8 = 10 sec. \[\therefore \] Average velocity \[(V)=\frac{50}{10}=5\]m/sec.