A) \[\frac{v}{g\mu }\]
B) \[\frac{g\mu }{v}\]
C) \[\frac{g}{v}\]
D) \[\frac{v}{g}\]
Correct Answer: A
Solution :
For equilibrium position, (v = 0) Force applied = Frictional force \[ma=\mu \,mg\] \[m\left( \frac{v}{t} \right)=\mu mg\]or \[t=\frac{v}{g\mu }.\]You need to login to perform this action.
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