question_answer

The dissociation equilibrium of a gas \[A{{B}_{2}}\] can be represented as \[2A{{B}_{2}}(g)\rightleftharpoons 2AB(g)+{{B}_{2}}(g)\] The degree of dissociation is x and is small compared to 1. The expression relating the degree of dissociation (x) with equilibrium constant \[{{K}_{p}}\] and total pressure p is

A)  \[\left( \frac{2{{K}_{p}}}{p} \right)\]                      

B)     \[{{\left( \frac{2{{K}_{p}}}{p} \right)}^{\frac{1}{3}}}\]    

C)     \[{{\left( \frac{2{{K}_{p}}}{p} \right)}^{\frac{1}{2}}}\]                    

D)     \[\left( \frac{{{K}_{p}}}{p} \right)\]