JIPMER Jipmer Medical Solved Paper-2014

  • question_answer
    Work function of a metal is \[5.2\times {{10}^{-18}},\] then its threshold wavelength will be

    A)  736.7 \[\overset{\text{o}}{\mathop{\text{A}}}\,\]          

    B)         760.7 \[\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C)  301 \[\overset{\text{o}}{\mathop{\text{A}}}\,\]            

    D)         344.4 \[\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: D

    Solution :

    Work function (W)\[=\frac{hc}{\lambda }\Rightarrow \lambda =\frac{hc}{W}\] Threshold wavelength \[(\lambda )=\frac{hc}{W}\] \[=\frac{6.626\times {{10}^{-34}}\times 2.97\times {{10}^{8}}}{5.2\times {{10}^{-18}}}\] \[\cong 344.4\,\overset{\text{o}}{\mathop{\text{A}}}\,.\]


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