A) \[\log \left( \frac{x}{m} \right)=\log K+\frac{1}{n}\log C\]
B) \[\log \left( \frac{m}{x} \right)=\log K+\frac{1}{n}\log C\]
C) \[\log \left( \frac{x}{m} \right)=\log C+\frac{1}{K}\log C\]
D) \[\log \left( \frac{x}{m} \right)=\log C+\frac{1}{n}\log K\]
Correct Answer: A
Solution :
Freundlich gave an empirical relationship between the quantity of gas adsorbed by unit mass of solid adsorbent and concentration at a particular temperature. \[\log x\text{/}m=\log K+\frac{1}{n}\log C\] \[x=\] mass of gas adsorbed, \[m=\] mass of adsorbent \[C=\]concentration, \[K,\] \[n=\] constants.You need to login to perform this action.
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