JIPMER Jipmer Medical Solved Paper-2015

  • question_answer
    A straight line conductor of length 0.4 m is moved with a speed of 7 m/s perpendicular to magnetic field of intensity 0.9\[Wb\text{/}{{m}^{2}}.\] The induced e.m.f. across the conductor is:

    A)  1.26 V           

    B)         2.52 V

    C)  5.24 V                  

    D)         25.2 V

    Correct Answer: B

    Solution :

    Given: Length of conductor \[(l)=0.4\,m;\] Speed = 7 m/s and magnetic field \[(B)=0.9\,Wb/{{m}^{2}}\]. We know that induced e.m.f. (V) \[=Blv\,\cos \theta =0.9\times 0.4\times 7\times \cos 0{}^\circ =2.52\,V.\]


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