A) 10\[\Omega \]
B) 20\[\Omega \]
C) 30\[\Omega \]
D) 40\[\Omega \]
Correct Answer: C
Solution :
Lower resistance on extreme left and upper resistance on extreme right are ineffective. We know that the resistance \[{{R}_{2}}\] and \[{{R}_{3}}\] are in series combination. Therefore their equivalent resistance \[(R)={{R}_{2}}+{{R}_{3}}=10+10=20\,\Omega .\] Similarly, the resistance\[{{R}_{5}}\]and\[{{R}_{6}}\]are in series combination. Therefore their equivalent resistance \[(R)={{R}_{5}}+{{R}_{6}}=10+10=20\,\Omega .\] Now the equivalent resistances \[R\] and \[R\] are in parallel combination. Therefore their equivalent resistance \[(R)=\frac{RR}{R+R}=\frac{20\times 20}{20+20}=\frac{400}{40}=10\,\Omega \] Thus equivalent resistance between A and D \[(R)={{R}_{1}}+R+{{R}_{4}}=10+10+10\] \[=30\,\Omega \] (series combination)
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