JIPMER Jipmer Medical Solved Paper-2015

  • question_answer
    The magnetic field \[dB\] due to a small current element\[dl\]at a distance\[\vec{r}\]and element carrying current\[i\]is:

    A)  \[dB=\frac{{{\mu }_{0}}}{4\pi }i\left( \frac{dl\times \vec{r}}{r} \right)\]

    B)  \[dB=\frac{{{\mu }_{0}}}{4\pi }{{i}^{2}}\left( \frac{dl\times \vec{r}}{{{r}^{2}}} \right)\]

    C)  \[dB=\frac{{{\mu }_{0}}}{4\pi }{{i}^{2}}\left( \frac{dl\times \vec{r}}{r} \right)\]

    D)  \[dB=\frac{{{\mu }_{0}}}{4\pi }i\left( \frac{dl\times \vec{r}}{{{r}^{3}}} \right)\]

    Correct Answer: D

    Solution :

    We know that according to Biot-Savert law, \[dB\propto i\left( \frac{dl\times \vec{r}}{{{r}^{3}}} \right)=\frac{{{\mu }_{0}}}{4\pi }i\left( \frac{dl\times \vec{r}}{{{r}^{3}}} \right).\]


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