JIPMER Jipmer Medical Solved Paper-2015

  • question_answer
    A hospital uses an ultrasonic scanner to locate tumours in a tissue. The operating frequency of the scanner is 4.2 MHz. The speed of sound in a tissue is 1.7 km/s. The wavelength of sound in the tissue is close to:

    A)  \[4\times {{10}^{-4}}\,m\]       

    B)         \[8\times {{10}^{-4}}\,m\]

    C)  \[4\times {{10}^{-3}}\,m\]       

    D)         \[8\times {{10}^{-3}}\,m\]

    Correct Answer: A

    Solution :

    Given: Frequency (n)\[=4.2\text{ }MHz=4.2\times {{10}^{6}}\,Hz\] and speed of sound \[(c)\,=1.7\,km/s\,=1.7\,\times {{10}^{3}}6\,m/s\]. We know that wave length of sound in tissue \[\lambda =\frac{c}{n}=\frac{1.7\times {{10}^{3}}}{4.2\times {{10}^{6}}}=4\times {{10}^{-4}}m.\]


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