A) 15 A
B) 50 A
C) 75 A
D) 125 A
Correct Answer: B
Solution :
Given: Input voltage in primary\[({{\varepsilon }_{p}})=230V;\] Current in secondary \[({{I}_{s}})=2A\] and ratio of primary to secondary windings\[{{N}_{p}}:{{N}_{s}}=1:25\]. We know that ratio of current in primary to secondary\[\frac{{{I}_{p}}}{{{I}_{s}}}=\frac{{{N}_{s}}}{{{N}_{p}}}=\frac{25}{1}.\] Therefore current in the primary\[{{I}_{p}}={{I}_{s}}\times \frac{25}{1}=2\times \frac{25}{1}=50A.\]
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