A) 1000 W
B) 40 W
C) 20 W
D) 0 W
Correct Answer: D
Solution :
Given: Current \[(I)=5\,\sin \,(100\,t-\pi \text{/}2)\]and voltage (V) = 200 sin (100 t). Comparing the given equation, with the standard equation, we find that between current and voltage is \[\phi =\frac{\pi }{2}=90{}^\circ .\] Therefore power (P)\[=\text{IV}\,\cos \phi =\text{IV}\,\cos 90{}^\circ \] \[=\text{IV}\times 0=0\,W.\]You need to login to perform this action.
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